16t^2-2t=30

Solution for 16t^2-2t=30 equation:

16t^2-2t=30

We move all terms to the left:

16t^2-2t-(30)=0

a = 16; b = -2; c = -30;
Δ = b2-4ac
Δ = -22-4·16·(-30)
Δ = 1924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1924}=\sqrt{4*481}=\sqrt{4}*\sqrt{481}=2\sqrt{481}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{481}}{2*16}=\frac{2-2\sqrt{481}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{481}}{2*16}=\frac{2+2\sqrt{481}}{32}
$